Oh man! Did I have to work to find this one! Boron was kind of a holy
grail for me, I spent years puzzling over it. For many years the only solutions
I had were P1, N1, P2, N2. All of them had features in common... all the quarks
were equidistant on the surface of the shell, and all of them could be
solved with two loop sizes. I falsely believed that all nuclear shells
would have their quarks spaced equidistant, and I just could not find such
a solution for boron. I knew it was special in several ways, and I was sure
that finding a solution for the fifteen quark shells of boron would be the
key to understanding nuclear structure. I studied the
boron hydrides, planar molecules folded on themselves
by charge. Boron is a semiconductor, and I was hoping to confirm a metallic
bonding model using its nuclear structure as a guide. I just couldn't get it
though, and I was certain that two different isotopes of boron were involved in
the boron hydrides. At the very least, radical strings were in different pinning
sites. The 3rd degree solution for P5 has a startling number of radical strings, five of them. There are no genuine down quarks on the 3rd degree P5, only bogus down quarks. (The 4th degree solution offers only two radical strings.) The first photo shows P5 stripped of radical strings, the remaining photos show two possible pinning configurations, but there are many more. The neutron shell will ultimately decide the final pinning points, but since boron typically has five or six neutrons, the final stacking solutions should still have some flexibility in their pinning sites. |
Required Snap Points: 50 Available Snap Points: 45 Pinned Vector Bosons: 5 | |
L1 = 37.2007141" (Structural) L2 = 39.11514559" (Equatorial) L3 = 14.94064195" (Polar) |
Model Diameter: 12.45073754" Loop Ratios: (1:2): 0.951056516 (1:3): 2.48990065 (2:3): 2.618036475 |
Loop Equation: 5(L1) + 1(L2) + 2(L3) = 255" | |
Snap Point Equation: 5(6) + 1(5) + 2(5) = 45 A.S.P. | PVB's: (+ 5 P.V.B. = 50 R.S.P.) |
Required Snap Points: 50 Available Snap Points: 50 Pinned Vector Bosons: 0 | |
L1 = 28.6729006" (Structural) L2 = 88.6041357" (Sinusoidal-Equatorial) L3 = 11.5156806" (Polar) |
Model Diameter: 9.596556646" Loop Ratios: (1:2): 0.333333333 (1:3): 2.48990065 (2:3): 7.694216149 |
Loop Equation: 5(L1) + 1(L2) + 2(L3) = 255" | |
Snap Point Equation: 5(6) + 1(10) + 2(5) = 50 R.S.P. |
This fourth degree solution for P5 pins two radical strings. I have successfully stacked this shell with (N5-41P) to form a B10 (Boron) nucleus with a complementary shell structure, and have further identified it as a valid solution set from studies of the boron hydrides and predictions made in my 1989 paper "Time and Geometry." But please, don't take my word for it, go verify it yourself, after all, that's why this web site exists. The pinning sites in the stacked model differ from what is shown here, but recall that I pin the strings for individual shells in a way that best balances their charge structure. Actually stacking the shells is the only way to determine the appropriate pinning sites for vector bosons (radical strings). |
Required Snap Points: 50 Available Snap Points: 48 Pinned Vector Bosons: 2 | |
L1 = 34.07118437" (Structural) L2 = 35.82456329" (Equatorial) L3 = 13.68375255" (Polar) L4 = 21.45200976" (Filler) |
Model Diameter: 11.40331266" Loop Ratios: (1:2): 0.951056516 (1:3): 2.48990065 (1:4): 1.588251392 (2:3): 2.618036475 (2:4): 1.669986341 (3:4): 0.637877416 |
Loop Equation: 5(L1) + 1(L2) + 2(L3) + 1(L4) = 255" | |
Snap Point Equation: 5(6) + 1(5) + 2(5) + 1(3) = 48 A.S.P. | PVB's: (+ 2 P.V.B. = 50 R.S.P.) |